-
Consider the system described by following state space equations

x1̇ 
= 
0 1 

x1 
+ 
0 
u ; y = [1 0] 
x1 
x2̇ -1 -1 x2 1 x2
If u is unit step input, then the steady state error of the system is
-
- 0
-
1 2
-
2 3
- 1
Correct Option: A
Transfer function
| ⇒ C[SI - A]-1 .B. = [1 0] = | ![]() | ![]() | -1 | ![]() | ![]() | |||||
| 1 |
| Transfer function = | ||
| s2 + s + 1 |
| = | ||||
| 1 + G(s) | s2 + s + 2 |
| ⇒ G(s) = | ||
| s2 + s |
Steady state error for unit step
| ess = | = | ![]() | |
| 1 + Kp |
| ess = | ![]() | = | = 0 | |
| 1 + ∞ |

