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The transfer function V2(s) of the circuit shown below is V1(s) 
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0.5s + 1 s + 1 -
3s + 6 s + 2 -
s + 2 s + 1 -
s + 1 s + 2
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Correct Option: D

By voltage division rule
| v2(s) = | R + | ||
| s | V1(s) | ||
| 1 + | + | ||
| cs | cs | ||
| = | 10 × 103 + | = | |||||
| 100 × 10-6 s | |||||||
| v1(s) | 10 × 103 + | 104 + 11 | |||||
| 100 × 10-6 s | |||||||
| = | |||
| v1(s) | (s + 2) |