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A vertical pole AB is standing at the centre B of a square PQRS.If PR subtends an angle of 90° at the top, A of the pole, then the angle subtended by a side of the square at A is :
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- 30°
- 45°
- 60°
- None of these
- 30°
Correct Option: C
PA = PR
∠APB = ∠ARB = 45°
If PR = √2x :
PB = | ||
√2 |
From triangle APB ,
tan45° = | ⇒ AB = PB = | ||
PB | √2 |
∴ PA = √( x2 / 2 ) + ( x2 / 2 ) = √x2 = x
∴ QA = PQ = PA = x
∴ ∠PAQ = 60°