If y is the solution of the differential equation y3dy +

If y is the solution of the differential equation y³ dy + x³ = 0 ,
dx

y(0) = 1 the value of y(–1) is

y³	dy	= -x³
	dx

y³ dy = -x³ dx
∫ y³ dy = -∫ x³ dx

y⁴	=	− x⁴	+ c
4		4

	x⁴ + y⁴	= c
	4

y(0) = 1 ,

	0 + 1	= c
	4

c =	1
	4

x⁴ + y⁴ = 1
y = 4√1 - x⁴
when x = -1
y = 0

If y is the solution of the differential equation y³	dy	+ x³ = 0 ,
	dx