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The second moment of a circular area about the diameter is given by (D is the diameter)
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πD4 4
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πD4 16
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πD4 32
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πD4 64
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Correct Option: D
Polar Moment of Inertia perpendicular to the plane of paper.
Ip = | ||
32 |
Now, applying “Perpendicular Axes” Theorem.
Ix + Iy = Ip
⇒ 2Ix = Ip
⇒ Ix = | [ ∵ Ix = Iy ] | |
2 |
= | ||
64 |