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Strength Of Materials Miscellaneous

Strength Of Materials

  1. A circular rod of diameter d and length 3d is subjected to a compressive force F acting at the top point as shown below. Calculate the stress at the bottom most support point A

    1. 12F
      πd2

    2. 16F
      πd2

    3. -
      4F
      πd2

    4. -
      12F
      πd2
Correct Option: A


Stress due to Axial force

σa =
F
=
F
=
4F
(compressive)
A(π / 4)d2πd2

Stress due to bending:
σb =
My
=
Fd
×
d
=
16F
(tensile)
22
I
π
d4πd2
64

Combined stress:
σr = σa + σb
σr =
-4F
+
16F
=
12F
πd2πd2πd2

σr =
12F
πd2



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