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A rectangular hole of size 100 mm × 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 MPa and 300 MPa, respectively. The hole is made by punching process. Neglecting the effect of clearance, the punching force (in kN) is
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- 300
- 450
- 600
- 750
- 300
Correct Option: B
Perimeter = (50 + 100) × 2 = 300 , Thickness = 5
so shown Area = 300 × 5 = 1500 mm2.
Punching force = τ × As = 300 × 1500 = 450 KN