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3 blocks of B1, B2 and B3 are to be inserted in a channel of width S maintaining a minimum gap of width T = 0.125 mm, as shown in figure. For P = 18.75 ± 0.08, Q = 25.00 ± 0.12, R = 28.125 ± 0.1 and S = 72.35 + X. The tolerance X is
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- – 0.15
- 0.05
- – 0.05
- None of the above
Correct Option: C
Consider,P + Q + R + T(max.) = 18.83 + 25.12 + 28.225 + 0.125 = 72.3 = s
Given s = 72.35 + X
∴ 72.35 + X = 72.3 or X = – 0.05
