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In an interchangeable assembly, shafts of size –25.000+0.040-0.0100 mm mate with holes of size 25.000+0.020-0.000 mm. The maximum possible clearance in the assembly will be
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- 10 microns
- 20 microns
- 30 microns
- 60 microns
- 10 microns
Correct Option: D
Minimum shaft size = 25.000 – 0.04 = 24.96 mm Maximum hole size = (25.000 + 0.02) = 25.02 mm 
∴ Maximum possible clearance = Maximum size of hole – minimum size of shaft
Maximum possible clearance = 25.02 – 24.96 = 0.060 mm = 60 micron.
