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Below figure shows a rigid bar hinged at A and supported in a horizontal position by two vertical identical steel wires. Neglect the weight of the beam. The tension T1 and T2 induced in these wires by a vertical load P applied as shown are
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T1 = T2 = P 2 -
T1 = Pal , T2 = Pbl (a² + b²) (a² + b²) -
T1 = Pbl , T2 = Pal (a² + b²) (a² + b²) -
T1 = Pal , T2 = Pal 2(a² + b²) 2(a² + b²)
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Correct Option: B
Σy = O
T1 + T2 – P – RA = O –(i)
ΣMA = O
T1 (a) + T2 (b) = P (l) –(ii)
Using similar Δ’s in fig (2)
| = | ⇒ |  | Δl1 = | Δl2 = |  | ||||
| a | b | AE | AE |
| = | ||
| a | b |
Putting above eqn in eqn (ii)
| T1(a) + | T1 = P(l) | |
| a |
| T1 = | T2 = | ||
| (a² + b²) | (a² + b²) |
