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In a sheet metal of 2 mm thickness a hole of 10 mm diameter needs to be punched. The yield strength in tension of the sheet material is 100 MPa and its ultimate shear strength is 80 MPa. The force required to punch the hole (in kN) is
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- 5.026
- 8.026
- 5.028
- 19.08
Correct Option: A
F = πdt Ts = π × 10 × 2 × 80 = 5026.5 N = 5.026 kN