In an arc welding process, the voltage and current are 25

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In an arc welding process, the voltage and current are 25 V and 300 A respectively. The arc heat transfer efficiency is 0.85 and welding speed is 8 mm/s. The net heat input (in J/mm) is

1. 64
2. 797
3. 1103
4. 79700

Correct Option: B

V = 25 Volt, I = 300 A, η = 0.85
Weld speed = 8 mm/s.
Power Generated at arc = V.I
= 25 × 300 = 7500 J/S
Heat transferred = 0.85 × 7500
= 6375 J/S
So net Heat Input = 6375/8 = 797 J/mm.