Direction: A cylinder is turned on a lathe with orthogonal machining principle. Spindle rotates at 200 rpm. The axial feed rate is 0.25 mm per revolution. Depth of cut is 0.4 mm. The rake angle is 10°. In the analysis it is found that the shear angle is 27.75°.
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The thickness of the produced chip is
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- 0.511 mm
- 0.528 mm
- 0.818 mm
- 0.846 mm
Correct Option: A
Given, rake angle, α = 10º
shear angle, φ = 27.75
depth of cut, t1 = 0.4 mm
Let t2 = thickness of chip produced
| Now, | = | ||
| t2 | cos(φ − α) |
| ⇒ t2 = | |
| sinφ |
| = | |
| sin(27.75) |
| = | = 0.818 mm | |
| sin 27.75 |
