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In a machining operation, doubling the cutting speed reduces the tool life to 1/8th of the original value. The exponent n in Taylor's tool life equation VTn = C. is
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1 8 -
1 4 -
1 3 -
1 2
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Correct Option: C
Taylor’s tool life equation,
VTn = C ...(i)
Where, V = cutting speed and T = tool life
When cutting speed is doubled and tool life reduces to 1/8, then
2V | T | n | = C ...(ii) | |||
8 |
Dividing equation (i) by equation (ii), we get
= 1 | |||||
2V | |||||
n | |||||
8 |
or VTn = 2V | n | = 2Vn2−3n | |||
8 |
or 1 = 2⋅2−3n
or 1 = 2−3n + 1
or 2−3n + 1 = 20
or –3n + 1 = 0
or 3n = 1
or n = | . | |
3 |