Home » Materials Science and Manufacturing Engineering » Materials Science and Manufacturing Engineering Miscellaneous » Question

Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

Direction: In an orthogonal machining operation:
Uncut thickness = 0.5 mm
Cutting speed = 20 m/min
Rake angle = 15°
Width of cut = 5 mm
Chip thickness = 0.7 mm
Thrust force = 200 N
Cutting force = 1200 N
Assume Merchants theory.

  1. The values of shear angle and shear strain, respectively, are
    1. 30.3° and 1.98
    2. 30.3° and 4.23
    3. 40.2° and 2.97
    4. 40.2° and 1.65
Correct Option: D

Here, r = cutting ratio,

n =
t1
=
0.5
= 0.714
t20.7

∴  tanφ =
rcosα
1 − rsinα

where, φ = shear angle
and α = rake angle
∴  φ = 40.2º
Shear strain = cot φ + tan (φ – α) = 1.65



Your comments will be displayed only after manual approval.