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In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool, the cutting velocity is 90 m/min. The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm. If the orthogonal rake angle is zero and the principal cutting edge angle is 90°, the shear angle in degree is
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- 20.56
- 26.56
- 30.56
- 36.56
Correct Option: B
Chip thickness,
| r = | = | = 0.5 | ||
| chip thickness | 0.48 |
rake angle = 0
| tanφ = | = .5 | |
| 1 − sinα |
∴ φ = 26.56
