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A DC servomotor is directly driving an NC table. The pitch of the lead screw of the table is 5 mm. The motor rotates at 100 rpm for an applied voltage of 10 V. If the voltage speed characteristic of the motor is linear, the applied voltage for a table of 3 m/min is equal to
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- 30 V
- 60 V
- 33 V
- 50 V
Correct Option: B
Motor speed = 10 rpm.
Distance = travelled on
Lead screw = 5 mm.
Line for one revolution = 1/100 min.
Speed of motion on lead serew
| = | = 500 mm/ min. | |
| 100 |
Considering line characteristic of 0.5m/min to get travel speed of 3m/min, we have to increase the voltage by
| = | = 6 times | 0.5 |
i.e. 10 × 6 = 60 V
