Home » Thermodynamics » Thermodynamics Miscellaneous » Question

Direction: Consider a steam power plant using a reheat cycle as shown. Steam leaves the boiler and enters the turbine at 4 MPa, 350°C (h3 = 3095 kJ/kg). After expansion in the turbine to 400 kPa (h4 = 2609 kJ/kg), the steam is reheated to 350°C (h5 = 3170 kJ/kg), and then expanded in a low pressure turbine to 10 kPa (h6 = 2165 kJ/kg) the specific volume of liquid handled by the pump can be assumed to be

  1. The thermal efficiency of the plant neglecting pump work is
    1. 15.8%
    2. 41.1%
    3. 48.5%
    4. 58.6%
Correct Option: B

Given: h1 = 29.3 kJ/kg
h2 =?
h3 = 3095 kJ/kg
h4 = 2609 kJ/kg
h5 = 3170 kJ/kg
h6 = 2165 kJ/kg

Turbine work
WT = (h3 – h4) + (h5 – h6)
= (3095 – 2609) + (3170 – 2165) =
1491 kJ/kg
Q = Heat input = (h3 – h1) + (h5 – h4)
= (3095 – 29.3) + 3(3170 – 2609) = 3626.7 kJ/kg
∴ Thermal efficiency of the plant

=
1491
= 41.11%
3226.7



Your comments will be displayed only after manual approval.