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A cylindrical cup of 48.5 mm diameter and 52 mm height has a corner radius of 1.5 mm. Cold rolled steel sheet of thickness 1.5 mm is used to produce the cup. Assume trim allowance as 2 mm per 25 mm of cup diameter. What is the blank size in mm?
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- 102.0
- 115.4
- 120.5
- 128.5
Correct Option: B
= √d² + 4dh
D = √(48.5)² + 4 × 48.5 × 52
D = 111.53 mm
Trim Allowance = 2/25 × 48.5 = 3.88 mm.
Total blank size = 111.53 + 3.88 = 115.41 mm
