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In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was obtained at a cutting velocity of 20 m/min. Taking tool life exponent as 0.25, the tool life in minutes at 40 m/min of cutting velocity will be
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- 0.506
- 0.625
- 3.140
- 5.002
Correct Option: B
n = 0.25 V1 = 20m /min,
T1 = 10 min V2 = 40m/min, T2 =?
V1Tn1 = V2Tn2 = C
20 (T0)0.25 = 40 (T2)0.25
T2 = 0.625 min
