The following data pertain to a single stage impulse steam

The following data pertain to a single stage impulse steam turbine: Nozzle angle = 20° Blade velocity = 200 m/s Relative steam velocity at entry = 350 m/s Blade inlet angle = 30° Blade exit angle = 25° If blade friction is neglected the work done per kg steam is

Given :α = 20°
β = 30°
x = 350 cos 30° = 303 m/s
∴ V_wi = 303 + V_b
= 303 + 200 = 503 m/s

cos 25° =	200 + V_wo	= 0.9063
	350

V_wo =118 m/s
Work done/kg of steam

=	(V_wi + V_wo) V_b	kJ
	1000

=	(503 + 118) 200	= 124 kJ
	1000