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Propane (C3H8) is burned in an oxygen atmosphere with 10% deficit oxygen with respect to the stoichiometric requirement. Assuming no hydrocarbons in the products, the volume percentage of CO in the products is___.
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- 14.29%
- 13.29%
- 17.29%
- 15.29%
Correct Option: A
C3 H8 + xO2 → aCO2 + bH2 O
Carbon balance: a = 3
Hydrogen balance: 2b = 8 → b = 4
Oxygen balance:
2x = 2a + b
| → x = a + | = 3 + | = 5 | 2 | 2 |
For chemical correct or stoichiometric burning, no of moles of O2 required are = 5.
As it is burnt with 10% deficient oxygen, it will generate CO.
The new equation is
C3H8 + 0.9 × 5O2 → CO2 + bCO+ cH2O
Carbon balance: a + b = 3
Hydrogen balance: 2c = 8 → c = 4
Oxygen balance:
2a + b + c = 0.9 × 5 × 2 = 9
2a + b + c = 9
⇒ 2a + b + c ⇒ 2a + b = 5
a + b = 3
By solving these two equations a = 2 and b = 1
In the exhaust products the no, of moles of CO are 1.% by volume of CO in exhaust,
| = | × 100 = | × 100 | a + b + c | 2 + 1 + 4 |
| = | × 100 = 14.29% | 7 |
