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If √2 tan2θ = √6 and 0° < θ < 45°, then the value of sinθ + √3cosθ – 2tan2θ is
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2 3 -
4 3 - 2
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8 3
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Correct Option: B
√2 tan2θ = √6
| ⇒ tan2θ = | = √3 | |
| √2 |
⇒ tan2θ = tan 60°
⇒ 2θ = 60° ⇒ θ = 30°
∴ sinθ + √3 cosθ – 2 tan2θ
= sin 30° + √3 cos 30° – 2 tan230°
| = | + √3 × | – 2 | ![]() | ![]() | 2 | |||
| 2 | 2 | √3 |
| = | + | − | |||
| 2 | 2 | 3 |
| = | = | = | |||
| 6 | 6 | 3 |

