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(1 + sec 20° + cot 70°)(1 – cosec 20° + tan70°) is equal to
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- 0
- 1
- 2
- 3
Correct Option: C
(1 + sec 20° + cot 70°) (1 – cosec 20° + tan 70°)
= (1 + sec 20° + tan 20°) (1 – cosec 20° + cot 20°)
[∴ tan (90° – θ) = cotθ; cot (90° – θ) = tanθ]
| = | ![]() | 1 + | + | ![]() | ![]() | 1 − | + | ![]() | ||||
| cos20° | cos20° | sin20° | sin20° |
| = | ![]() | ![]() | ![]() | ![]() | ||
| cos20° | sin20° |
| = | |
| sin20°.cos20° |
| = | |
| sin20°.cos20° |
| = | |
| sin20°.cos20° |
| = | = 2 | |
| sin20°.cos20° |

