-
A sum of money invested at compound interest amounts to ₹ 650 at the end of first year and ₹ 676 at the end of second year. The sum of money is :
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- ₹ 600
- ₹ 540
- ₹ 625
- ₹ 560
Correct Option: C
As per the given in question ,
Interest on ₹ 650 for 1 year = 676 – 650 = ₹ 26
| So, r = | × 100 | |
| 650 |
⇒ r = 4% per annum
| P = | ||||
![]() | 1 + | |||
![]() | t | |||
| 100 | ||||
| P = | ||||
![]() | 1 + | |||
![]() | 1 | |||
| 100 | ||||
| = | = 650 × | = ₹ 625 | ||
| ( 26/25 ) | 26 |
Using the given formula :
Here, b – a = 1 , B = Rs 676, A = ₹ 650
| R% = | ![]() | − 1 | ![]() | × 100% | |
| A |
| R% = | ![]() | − 1 | ![]() | × 100% | |
| 650 |
| R% = | ![]() | ![]() | × 100% | |
| 650 |
| R% = | × 100% | |
| 650 |
| R% = | = 4% | |
| 25 |
| Amount = P | ![]() | 1 + | ![]() | 1 | |
| 100 |
| 650 = P | ![]() | 1 + | ![]() | |
| 100 |
| ⇒ P = | = ₹ 625 | |
| 104 |
Note : A sum at a rate of interest compounded yearly becomes ₹ A, in n years and ₹ A2 in (n + 1) years,
| then P = A1 | ![]() | ![]() | n | |
| A2 |




