-
If x = √3 , then the value of 
√1 + x + √1 − x 
is 2 √1 + x − √1 − x
-
- −√3
- –1
- 1
- √3
Correct Option: D
| x = | ⇒ | = | |||
| 2 | x | √3 |
By componendo and dividendo,
| = | ||
| 1 − x | 2 − √3 |
| ⇒ | = | × | |||
| 1 − x | 2 − √3 | 2 + √3 |
| = | = | ||
| (2 − 3 √3)(2 + √3) | 4 − 3 |
| ⇒ | = (2 + √3)2 | |
| 1 − x |
| ∴ | = | ||
| √1 − x | 1 |
By componendo and dividendo
| = | ||
| √1 + x − √1 − x | 2 + √3 − 1 |
| = | = | = √3 | ||
| √3 + 1 | √3 + 1 |
