In a quarterly examination a student secured 30% marks and

In a quarterly examination a student secured 30% marks and failed by 12 marks. In the same examination another student secured 40% marks and got 28 marks more than minimum marks to pass. The maximum marks in the examination is

Maximum marks in the examination = x (let)

=	40x	-	30x	= 12 + 28
	100		100

=	10x	= 40 ⇒ x = 40 × 10 = 400
	100

Aliter : Using Rule 22,
Here, m = 30%, n = 40%, p = 12, q = 28
∴ Maximum marks

=	100	× (p + q)
	(n - m)

=	100	× (12 + 28)
	(40 - 30)

=	100 × 40	= 400
	10