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If 4x² – 4x secθ + 1 = 0, then secθ + tanθ = ?
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- 2x
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1 2x
- 3x
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2x or 1 2x
- 2x
Correct Option: D
4x² – 4x secθ + 1 = 0
= 4x secθ = 4x² + 1
| = sec θ = | ||
| 4x |
∴ tanθ = √sec²θ - 1
| = √ |  |  | ² | - 1 | |
| 4x |
| = √ | ||
| 16x² |
| = ± | ||
| 4x |
∴ secθ + tanθ
| = | + | |||
| 4x | 4x |
| = | = | |||
| 4x | 4x |
= 2x
or, secθ + tanθ
| = | - | |||
| 4x | 4x |
| = | = | = | |||
| 4x | 4x | 2x |
