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  1. If A + B = 90°, then √
    tanA . tanB + tanA . cotB
    =
    sin²B
    = ?
    sinA . secBcos²A

    1. 2 tan A
    2. tan A
    3. tan²A
    4. 2cot²B
Correct Option: B

A + B = 90° ⇒ B = 90° – A

∴ √
tanA . tanB + tanA . cotB
-
sin²A
sinA .secBcos²A

∴ √
tanA . tan(90° - A) + tanA . cot(90° - A)
-
sin²(90° - A)
sinA .sec(90° - A)cos²A

∴ √
tanA . cotA + tanA . tanA
-
cos²A
sinA . cosecAcos²A

= √1 + tan²A - 1 = √tan²A = tanA



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