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If tan (A – B) = x, then the value of x is
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(tanA + tan B) (1 - tanA tanB) -
(tanA + tan B) (1 + tanA tanB) -
(tanA - tan B) (1 - tanA tanB) -
(tanA - tan B) (1 + tanA tanB)
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Correct Option: D
sin (A – B) = sinA . cosB – cosA . sinB
cos (A – B) = cosA . cosB + sinA . sinB
| ∴ | ||
| cos(A - B) |
| = | ⇒ tanA | |
| cosA.cosB - sinA.sinB |
| = | - | ||||
| cosA.cosB | cosA.cosB | ||||
| + | |||||
| cosA.cosB | cosA.cosB | ||||
+ (Dividing numerator and denominator by cosA cosB)
| = | |
| 1 + tanA.tanB |
