If 1² + 2² + 3² + ..... + p² =p(p +

If 1² + 2² + 3² + ..... + p² = p(p + 1)(2p + 1) , then 1² + 3² + 5² + ..... + 17² is equal to :
6

As we know that ,

1² + 2² + 3² + .... + p² =	p(p + 1)(2p + 1)
	6

∴ 1² + 3² + 5² + .... + 17² = (1² + 2² + 3² + ... + 17²) – (2² + 4² + ...+ 16²)
Required answer = (1² + 2² + 3² + ... + 17²) – 4 (1² + 2² + ... + 8²)

Required answer =	17(17 + 1)(34 + 1)	-	4 × 8(8 + 1)(16 + 1)
	6		6

Required answer =	17 × 18 × 35	-	4 × 8 × 9 × 17
	6		6

Required answer = 1785 – 816 = 969

If 1² + 2² + 3² + ..... + p² =	p(p + 1)(2p + 1)	, then 1² + 3² + 5² + ..... + 17² is equal to :
	6