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In ∆ ABC, E and D are points on sides AB and AC respectively such that ∠ABC = ∠ADE. If AE = 3 cm, AD = 2 cm and EB = 2 cm, then length of DC is
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- 4 cm
- 4.5 cm
- 5.0 cm
- 5.5 cm
- 4 cm
Correct Option: D
As per the given in question , we draw a figure triangle ABC 
Here , AE = 3 cm, AD = 2 cm and EB = 2 cm,
In ∆ ADE and ∆ ABC,
∠ABC = ∠ADE
∠A = ∠A
∴ ∆ ABC ~ ∆ ADE
| ∴ | = | = | |||
| AD | DE | AE |
| ∴ | = | ||
| AD | AE |
| ⇒ | = | ||
| 2 | 3 |
| ⇒ | = | ||
| 2 | 3 |
| ⇒ 2AC = 5 × 3 ⇒ AC = | |
| 2 |
⇒ DC = AC – AD
| DC = | - 2 = | = | |||
| 2 | 2 | 2 |
DC = 5.5 cm