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∆ ABC and ∆ DEF are similar. Also ∠A = ∠D and ∠B = ∠E. If 4AB = DE and BC = 12 cm, then EF is equal to
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- 3 cm
- 24 cm
- 16 cm
- 48 cm
- 3 cm
Correct Option: D
As per the given in question , we draw figures of two similar triangles ABC and DEF

Given that , ∠A = ∠D and ∠B = ∠E and BC = 12 cm
∆ ABC ~ ∆ DEF and 4AB = DE
| ⇒ | = | ||
| DE | 4 |
| ∴ | = | ||
| DE | EF |
| ⇒ | = | ||
| 4 | EF |
⇒ EF = 48 cm.