Iftan θ + cot θ= 2, (0 ≤ θ ≤ 90°),then

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		tan θ + cot θ	=	2
		tan θ - cot θ		1

By componendo and dividendo,

		2 tan θ	=	3
		2 cot θ		1

⇒		sin θ	.	sin θ	= 3
		cos θ		cos θ

&rArr sin² θ = 3cos² θ
&rArr sin² θ = 3 (1 – sin² θ)
&rArr 4 sin² θ = 3

⇒ sin² θ =	3
	4

⇒ sin θ =	√3
	2

If	tan θ + cot θ	= 2, (0 ≤ θ ≤ 90°),then the value of sin θ is
	tan θ - cot θ