If tan (2θ + 45°) = cot 3θ where (2θ

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If tan (2θ + 45°) = cot 3θ where (2θ + 45°) and 3θ are acute angles, then the value of θ is

tan (2θ + 45°) = cot 3θ
= tan (90° – 3θ )
⇒ 2θ + 45° = 90° – 3θ
⇒ 5θ = 90° – 45° = 45°
∴ θ = 9°