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  1. If cos θ + secθ = 2, the value of cos6θ + sec6θ is
    1. 4
    2. 8
    3. 1
    4. 2
Correct Option: D

cosθ + secθ = 2

⇒ cos θ +
1
= 2
cos θ

⇒ cos²θ – 2 cosθ + 1 = 0
⇒ (cosθ – 1)² = 0
⇒ cosθ = 1
⇒ secθ = 1
∴ cos6θ + sec6θ = 1 + 1 = 2


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