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  1. the value of sec θ1 + sin θ+cos θ- 2tan²θ is
    cos θ1 + sin θ
    1. 4
    2. 1
    3. 2
    4. 0
Correct Option: C

Expression

= sec θ1 + sin θ+cos θ- 2 tan²θ
cos θ1 + sin θ

=
1 + sin² θ + 2sin θ + cos² θ
- 2 tan² θ
cos² θ(1 + sin θ)

=
2
- 2 tan² θ
cos² θ

= 2 sec² θ - 2 tan² θ
=2(sec² θ - tan² θ) = 2


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