If secθ + tanθ = 5, then the value of tan (tanθ

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secθ + tanθ = 5
∴ sec²θ – tan²θ = 1
⇒ (secθ – tanθ) (secθ + tanθ) = 1

⇒ secθ – tanθ =	1
	5

∴ (secθ + tanθ) – (secθ – tanθ)

= 5 -		1	=	25 - 1
		5		5

⇒ 2tanθ =		24	⇒ tanθ =	12
		5		5

=	17
	7