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  1. If sec α + tan α = 2, then the value of sin α is
    (assume that 0 < α < 90°)
    1. 0.4
    2. 0.5
    3. 0.6
    4. 0.8
Correct Option: C

sec α + tan α = 2

1
+
sin α
= 2
cos αcos α

1 + sin α
= 2
cos α

⇒ 1 + sin α = 2 cosα
⇒ (1+ sinα)² = 4 cos²α
⇒ 1 + sin²α + 2 sin α = 4(1 – sin²α)
⇒ 1+ sin²α + 2 sinα = 4 – 4 sin²α
⇒ 5 sin²α + 2 sinα + 1 – 4 = 0
⇒ 5 sin²α + 2 sinα – 3 = 0
⇒ 5 sin²α + 5 sinα – 3 sinα – 3 = 0
⇒ 5 sinα (sinα +1) – 3 (sinα +1) = 0
⇒ (5 sinα – 3) (sinα +1) = 0
∵α < 90°,
∴ 5 sinα – 3 = 0
⇒ 5 sinα = 3
⇒ sin α =
3
= 0.6
5



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