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  1. If 0° < A < 90°, the value of
    tan A – sec A –1
    is
    tan A + sec A + 1
    1. sin A – 1
      cos A
    2. 1 - sin A
      cos A
    3. 1 - cos A
      sin A
    4. sin A + 1
      cos A
Correct Option: A

=
tanA - secA - 1
tanA + secA + 1

=
tanA - secA - (sec²A - tan²A)
tanA + secA + 1

=
(tanA – secA) – (secA – tanA)(secA tanA)
tanA + secA + 1

=
(tanA – secA) + (tanA – secA)(secA tanA)
tanA + secA + 1

=
(tanA – secA)(1 secA tanA)
tanA + secA + 1

= tanA – secA =
sinA
-
1
cosAcosA

=
sinA - 1
cosA



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