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If 0° < A < 90°, the value of tan A – sec A –1 is tan A + sec A + 1
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sin A – 1 cos A -
1 - sin A cos A -
1 - cos A sin A -
sin A + 1 cos A
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Correct Option: A
= | tanA + secA + 1 |
= | tanA + secA + 1 |
= | tanA + secA + 1 |
= | tanA + secA + 1 |
= | tanA + secA + 1 |
= tanA – secA = | - | cosA | cosA |
= | cosA |