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  1. If secθ + tanθ = p, (p ≠ 0) then secθ is equal to
    1. p - 1, p ≠ 0
      p
    2. 2p - 1, p ≠ 0
      p
    3. p + 1, p ≠ 0
      p
    4. (1 / 2)p + 1, p ≠ 0
      p
Correct Option: D

secθ + tanθ = p .....(i)
∵ sec²θ – tan²θ = 1
⇒ (secθ + tanθ) (secθ – tanθ) = 1

⇒ secθ – tanθ =
1
....(ii)
p

On adding both the equations
2 secθ = p +
1
p

⇒ secθ =
1
p + 1
2p



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