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10 signals, each band-limited to 5 kHz are to be transmitted over a single channel by frequency division multiplexing. If AM-SSB modulation guard band of 1kHz is used then the bandwidth of the multiplexed signal will be—
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- 79 kHz
- 60 kHz
- 59 kHz
- 61 kHz
- 79 kHz
Correct Option: C
The total signal bandwidth 5 × 10 = 50 kHz there will be 9 guard band between 10 signal, so guard bandwidth 9 kHz
Total bandwidth = 50 + 9 = 59 kHz.
