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For the circuit shown below each diode has Vγ = 0.7 V. The V0 for – 10 ≤ Vs < 10 V is:
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- NA
- NA
- NA
- NA
- NA
Correct Option: D
For Vs > 0, when D1 is OFF, current will flow through diode D2 and is given by:
i = | = 0.465 mA | |
10 + 10 |
νo = 10 × i = 10 × 0.465 = 4.65 V
it means we conclude that
νo = νs for 0 < νs < 4.65 V
for negative values of νs, we get the same output but in negaive magnitude.
Hence alternative (D) is the correct choice.