A symmetrical 5 kHz square wave whose output varies between

A symmetrical 5 kHz square wave whose output varies between + 10 V and – 10 V is impressed upon the clipping circuit shown below. If diode has r_f = 0 and r_r = 2 MΩ and V_r = 0, the output waveform is:

The diode will conduct when ν_i < 2.5 V → V_o = Vi diode will not conduct when ν_i > 2.5 i.e., diode is open with 2 MΩ resistance.

ν_o = 2.5 V +	( ν_i - 2.5 ) × 1
	1 + 2

ν_o = 2.5 V +	ν_i - 2.5
	3

ν_o = 2.5 V +	10 - 2.5	= 5 V	( when v_i = 10V)
	3

when v_i < 2.5 V, V_o = V_i = – 10V which is given in option (B)
Hence alternative (B) is the correct choice.