The parameter of the transistor in fig given below VTN =

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The parameter of the transistor in fig given below V_TN = 1.2 V, K_n = 0.5 mA/V². The voltage V_DS is:

1. 2.83 V
2. 6.52 V
3. 3.48 V
4. 4.98 V 50 µA 5 V 5 V

Correct Option: B

Given that V_TN = 1.2 V
K_n = 0.5 mA/V²
I_D = K_n (V_S – V_TN)²
50 × 10^{– 6} = 0.5 × 10^{– 3} (V_GS – 1.2)²
V_GS = √.1 + 1.2 = 1.516 V
V_G = 0
so V_GS = V_G – V_S
or V_S = V_G – V_GS = 0 – 1.516
= – 1.516 V
V_DS = V_D – V_S = 5 – (– 1.516)
= 6.516 V