-
The parameter of the transistor in fig. below are VTN = 0.6 V and Kn = 0.2 mA/V2. The voltage Vs is:
-
- 1.72 V
- – 1.72 V
- 7.28 V
- – 7.28 V
Correct Option: B
Given that VTN = 0.6 V
Kn = 0.2 mA/V2
ID = 0.25 mA
ID = Kn (VGS – VTn)2
0.25 × 10– 3 = 0.2 × 10– 3 (VGS – 0.6)2
| = (VGS – 0.6)2 | ||
| 20 |
| VGS = | + 0.6 = 1.718 ≈ 1.72 | |
| √20 |
VG = 0 V
VGS = VG – VS
or VS = VG – VGS = 0 – 1.72 = – 1.72 V
Hence (B) is the correct choice.
