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An amplifier with mid band gain A = 500 has negative feedback applied of value β = 1/100. Given the upper cut off frequency without feedback was 60 kHz. With feedback it becomes:
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- 10 kHz
- 12 kHz
- 300 kHz
- 360 kHz
Correct Option: D
Given that
β = | ||
100 |
A = 500
fH = 60 kHz
After feedback. New upper cut-off frequency increases as bandwidth increases after feedback.
fH* = fH (1 + Aβ)
= 60 | 1 + | = 60 × 6 = 360 kHz | |||
100 |