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Analog electronics circuits miscellaneous

Analog Electronic Circuits

  1. The high frequency response of an amplifier is given by
    A =
    A0
    1 + j
    ω
    ω2

    where A0 = 1000 and ω2 = 104. Negative feedback with β = 9/1000 is now given. The value of ω2 now is:
    1. 104
    2. 103
    3. 105
    4. none of these
Correct Option: C

From given high frequency response

A =
A0
1 + j
ω
ω2

where, ω2 is the higher cut-off frequency.
and due to negative feedback ω2 increases, so the new,
ω2* = ω2 (1 + Aβ)
= 1041 + 1000 ×
9
= 104. 10 = 105
1000

Hence alternative (C) is the correct choice.



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