For fig. at time t 0 after the switch K was closed, it is

For fig. at time t ₀ after the switch K was closed, it is found that V₂ = + 5 V, determine the value of i ₂ (t ₀) and d / dt i₂ (t ₀)—

1. 2.5 amp, 5 amp/sec
2. 2.5 amp, 2.5 amp/sec
3. 5 amp, 2.5 amp/sec
4. 5 amp, 5 amp/sec

Given V₂ = 5V

I ₁ =		10 – V₂	=	10 – 5	= 5
		1		1

I ₃ =	5	= 2.5
	2

I ₂ = I₁ – I₃ = 5 – 2.5 = 2.5 amp.
Voltage across 1 Ω resistance = 2.5 × 1 = 2.5 V
V_L = 5 – 2.5 = 2.5 V

Also, V_L = L	di(t)
	dt

2.5 = 1 / 2	di₂(t₀)
	dt

or	di₂(t₀)	= 2.5 × 2 = 5 amp/sec
	dt