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The value of current I flowing in 5 Ω resistor in the figure, is—
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- 10 amp
- 2 amp
- 5 amp
- 7 amp
Correct Option: B
Apply the superposition theorem in the given circuit
Case I. When 10 V source is treated 5 A current source is replaced by their internal resistance (i.e. open circuited)
Now, 10 = 5 I ⇒ 1 = 2 Amp.
Case II. When current source (5 A) is treated and voltage source (10 V) S.C. the circuit becomes
According to the current division rule I will be zero so, the net current I = 2 amp.